3pqqp2 \frac{3pq}{qp^2\:}\:qp23pq
135−(−28)−63135-\left(-28\right)-63135−(−28)−63
(8x+2y)3\left(8x+2y\right)^3(8x+2y)3
(1+cos(3x))2\left(1+\cos\left(3x\right)\right)^2(1+cos(3x))2
∫15x+8dx\int\frac{1}{\sqrt{5x+8}}dx∫5x+81dx
8x3−4x2−2x−52x−1\frac{8x^3-4x^2-2x-5}{2x-1}2x−18x3−4x2−2x−5
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