Exercise
$\frac{6x^2-3x-1}{2x+1}$
Step-by-step Solution
1
Divide $6x^2-3x-1$ by $2x+1$
$\begin{array}{l}\phantom{\phantom{;}2x\phantom{;}+1;}{\phantom{;}3x\phantom{;}-3\phantom{;}\phantom{;}}\\\phantom{;}2x\phantom{;}+1\overline{\smash{)}\phantom{;}6x^{2}-3x\phantom{;}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}2x\phantom{;}+1;}\underline{-6x^{2}-3x\phantom{;}\phantom{-;x^n}}\\\phantom{-6x^{2}-3x\phantom{;};}-6x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}2x\phantom{;}+1-;x^n;}\underline{\phantom{;}6x\phantom{;}+3\phantom{;}\phantom{;}}\\\phantom{;\phantom{;}6x\phantom{;}+3\phantom{;}\phantom{;}-;x^n;}\phantom{;}2\phantom{;}\phantom{;}\\\end{array}$
$3x-3+\frac{2}{2x+1}$
Final answer to the exercise
$3x-3+\frac{2}{2x+1}$