$\lim_{x\to2}\left(\frac{x+2}{\left(x-2\right)^8}\right)$
$25y^2\:-\:121b^2$
$5x-4<3x-7$
$\frac{5}{8}x^2y\:\left(+5x^2-6xy+3y^2\right)$
$4x^2-x+2>0$
$\frac{3^n+3+4n+n^2}{3^{n+1}.\left(n+1\right).\left(n+3\right)}$
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