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Exercise

$\frac{6y}{5}=x^2+9x-5$

Step-by-step Solution

1

Multiply both sides of the equation by $5$

$6y=5\left(x^2+9x-5\right)$
2

Divide both sides of the equation by $6$

$\frac{6y}{6}=\frac{5\left(x^2+9x-5\right)}{6}$
3

Simplify the fraction $\frac{6y}{6}$ by $6$

$y=\frac{5\left(x^2+9x-5\right)}{6}$

Final answer to the exercise

$y=\frac{5\left(x^2+9x-5\right)}{6}$

Try other ways to solve this exercise

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  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
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Similar Questions Solved

$\log_3\left(81\right)=4$

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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