−9x−9x−9-9x-9x-9−9x−9x−9
∫ 10(x+1)(x2+2x+3)4 dx\int\:\:\:10\left(x+1\right)\left(x^2+2x+3\right)^4\:dx∫10(x+1)(x2+2x+3)4dx
2(3+x)<3x−82\left(3+x\right)<3x-82(3+x)<3x−8
−6cos(a)=3cos(a)+8-6cos\left(a\right)=3cos\left(a\right)+8−6cos(a)=3cos(a)+8
(+9)−((+3)−(3−12)−(+8))\left(+9\right)-\left(\left(+3\right)-\left(3-12\right)-\left(+8\right)\right)(+9)−((+3)−(3−12)−(+8))
9x2−30x+25=09x^2-30x+25=09x2−30x+25=0
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