Exercise
\frac{8x^5 - 19x^4 + 11x^2 - 11}{x - 2}
Step-by-step Solution
1
Math interpretation of the question
$\frac{8x^5-19x^4+11x^2-11}{x-2}$
2
Divide $8x^5-19x^4+11x^2-11$ by $x-2$
$\begin{array}{l}\phantom{\phantom{;}x\phantom{;}-2;}{\phantom{;}8x^{4}-3x^{3}-6x^{2}-x\phantom{;}-2\phantom{;}\phantom{;}}\\\phantom{;}x\phantom{;}-2\overline{\smash{)}\phantom{;}8x^{5}-19x^{4}\phantom{-;x^n}+11x^{2}\phantom{-;x^n}-11\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x\phantom{;}-2;}\underline{-8x^{5}+16x^{4}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{-8x^{5}+16x^{4};}-3x^{4}\phantom{-;x^n}+11x^{2}\phantom{-;x^n}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n;}\underline{\phantom{;}3x^{4}-6x^{3}\phantom{-;x^n}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;\phantom{;}3x^{4}-6x^{3}-;x^n;}-6x^{3}+11x^{2}\phantom{-;x^n}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n;}\underline{\phantom{;}6x^{3}-12x^{2}\phantom{-;x^n}\phantom{-;x^n}}\\\phantom{;;\phantom{;}6x^{3}-12x^{2}-;x^n-;x^n;}-x^{2}\phantom{-;x^n}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n;}\underline{\phantom{;}x^{2}-2x\phantom{;}\phantom{-;x^n}}\\\phantom{;;;\phantom{;}x^{2}-2x\phantom{;}-;x^n-;x^n-;x^n;}-2x\phantom{;}-11\phantom{;}\phantom{;}\\\phantom{\phantom{;}x\phantom{;}-2-;x^n-;x^n-;x^n-;x^n;}\underline{\phantom{;}2x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{;;;;\phantom{;}2x\phantom{;}-4\phantom{;}\phantom{;}-;x^n-;x^n-;x^n-;x^n;}-15\phantom{;}\phantom{;}\\\end{array}$
$8x^{4}-3x^{3}-6x^{2}-x-2+\frac{-15}{x-2}$
Final answer to the exercise
$8x^{4}-3x^{3}-6x^{2}-x-2+\frac{-15}{x-2}$