$\sqrt[5]{25^{4x+1}}=\sqrt[4]{125^{2x+2}}$
$9\left(7+4n\right)$
$x^2-8\le0$
$\frac{-48m^{-4}n^2}{+20m^{-3}n^4}$
$4x^{2}+3xy=11$
$\int-3\left(x^{3}+1\right)dx$
$\frac{x^3+x-1}{x^2+3}$
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