$\frac{x^3-3^3}{x+3}$
$4\frac{1}{4}\:x\:4\:\frac{1}{5}$
$\frac{\left(4x^2+12x-10\right)}{4}$
$v^2+12v+36$
$\log\left(x^2+1\right)-\log\left(x^2-1\right)=\log\frac{13}{12}$
$\frac{6}{x^4+6x}$
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