$\int\frac{-3}{\left(x+4\right)}dx$
$\lim_{x\to\infty}\left(\frac{8}{x^2}-\sqrt{x}\right)$
$\int\frac{x-1}{x^3+2x^2+x}dx$
$\arctan\left(tan\left(\frac{28\pi}{17}\right)\right)$
$4\sqrt[2]{x}+2\sqrt{9x}-\sqrt{16x}$
$3x-y=-13\:\:\:$
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