$\frac{4}{7}+\frac{1}{4}\cdot\frac{2}{5}+\frac{1}{6b}$
$\left(-3x^2-4y\right)^2$
$\int x^3\:sqrt\left(1-x^2\right)dx$
$\left(-12\:+\:3\:+\:9\right)\:.\:\left(-25\:+\:38\:-110\right).\:\left(\:-18\:+\:34\:-\:15\right)$
$\frac{x}{1.9}=-4.7$
$x^3-p^3$
$5x-y=-9$
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