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Exercise

$\frac{d^2y}{dx^2}\left(3x^3-9x^2+3x-499\pi\right)$

Step-by-step Solution

1

Multiply the single term $\frac{d^2y}{dx^2}$ by each term of the polynomial $\left(3x^3-9x^2+3x+499\cdot -\pi \right)$

$3x^3\left(\frac{d^2y}{dx^2}\right)-9x^2\left(\frac{d^2y}{dx^2}\right)+3x\left(\frac{d^2y}{dx^2}\right)+499\cdot -\pi \left(\frac{d^2y}{dx^2}\right)$

Final answer to the exercise

$3x^3\left(\frac{d^2y}{dx^2}\right)-9x^2\left(\frac{d^2y}{dx^2}\right)+3x\left(\frac{d^2y}{dx^2}\right)+499\cdot -\pi \left(\frac{d^2y}{dx^2}\right)$

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