$\int\left(\frac{x}{\left(1-4x^2\right)^2}\right)dx$

$5=x^2-4$

$\left(wx-4\right)\left(wx+4\right)$

$\lim_{x\to0}\left(\frac{\left(cos\left(4x\right)-1\right)}{\left(\left(e^3x\right)-3x-1\right)}\right)$

$\frac{\left(\frac{1}{sin\left(x\right)}.cos\left(x\right)\right)}{-\csc^2\left(x\right)}=\:\left(-cos\left(x\right).sin\left(x\right)\right)$

$64\:-\:25q^4\:$