$\left(\frac{13}{9}a^5+\frac{3a^3}{4b^6}\right)^2$
$\frac{dy}{dx}=y\left(1-2x\right)$
$\sqrt{9.5}$
$5x\:+\:1\:<\:6$
$\lim_{x,y\to0,0}\left(\frac{3xy^3}{x^2+y^6}\right)$
$\frac{2x+6}{2}-x=3$
$1+2+3+4+5+5$
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