$\frac{5}{d+7}=\frac{2}{b-5}$
$0=-5n-2n$
$\left(2x^2+23\right)\left(2x+3\right)$
$\lim_{x\to0\:}\frac{3x+2}{x-2}$
$\frac{d^2}{dx^2}\left(4-x^4-x^3\right)$
$9\:-\left(-7\right)-\:\left(3\right)^4:\left(-3\right)^3$
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