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Exercise

$\frac{d}{dx}\left(\sqrt[3]{\frac{x-1}{x^3e^{6x}}}\right)$

Final answer to the exercise

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Other solved exercises

$10+x<6$

$\frac{2x+2}{3x-6}\ge3$

$x^2-8x+4=0$

$2x^2-6x+3x+4x$

$5x^3-9x^2-6x+8$

$-4.2\:x\:6.5$
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