$\int_0^{\pi}18senxdx$
$1-\sec\left(x\right)^2=\tan\left(x\right)^2$
$\int x^2\left(3x^3-5\right)^{\frac{3}{4}}dx$
$x^3+8x^2+21x+18$
$-3\cdot32\cdot\left(-3\right)^1+2\cdot\left(-5\right)^2\cdot\left(-3\right)^0+35\cdot2^2-1500\cdot\left(-5\right)^0\cdot2^0\cdot\left(-3\right)^0$
$2\int\tan\left(x\right)\sec\left(x\right)dx$
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