$v^2+5v+3v$
$4^{x+3}=\left(\frac{1}{2}\right)^x$
$\int sen^2cos^4t\:dt$
$\left(3x^2\right)\left(\frac{2}{5}\right)\left(x^3\right)$
$8\frac{1}{2}-2+4\frac{3}{4}$
$x\ge6-x$
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