2x−1≤5x+142x-1\le5x+142x−1≤5x+14
5⋅10−3(3−8)5\cdot10-3\left(3-8\right)5⋅10−3(3−8)
f(x)=2x−6f\left(x\right)=2x-6f(x)=2x−6
−14x−7=77-14x-7=77−14x−7=77
x2−10xy+25y2x^2-10xy+25y^2x2−10xy+25y2
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