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limx→+1(sinx−sin1x−1)\lim_{x\to+1}\left(\frac{sinx-sin1}{x-1}\right)x→+1lim(x−1sinx−sin1)
limx→0(2ex+65lnx+3)\lim_{x\to0}\left(\frac{2e^x+6}{5lnx+3}\right)x→0lim(5lnx+32ex+6)
13x3+12x2\frac{1}{3}x^3+\frac{1}{2}x^231x3+21x2
1200a−1bc3800ab−2c\frac{1200a^{-1}bc^3}{800ab^{-2}c}800ab−2c1200a−1bc3
x+4≥3 x+4\ge3\:\:x+4≥3
limx→1(ln(1+x)4)\lim_{x\to1}\left(ln\left(1+x\right)^4\right)x→1lim(ln(1+x)4)
−(−14)+(−37)-\left(-14\right)+\left(-37\right)−(−14)+(−37)
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