Exercise
\frac{d}{dx}3x^4y - 2x^3y - 6x + 8 y = 0
Step-by-step Solution
Learn how to solve special products problems step by step online. \frac{d}{dx}3x^4y - 2x^3y - 6x + 8 y = 0. Math interpretation of the question. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the linear function times a constant, is equal to the constant. The derivative of the linear function is equal to 1.
\frac{d}{dx}3x^4y - 2x^3y - 6x + 8 y = 0
Final answer to the exercise
$12yx^{\left(4y-1\right)}-6yx^{\left(3y-1\right)}-6$