$$6x-\left(x-5\right)<\left(3-2x\right)\cdot\:5$$

$$\frac{d}{dx}\left(4x^3y^2=4x^2-4xy\right)$$

$$16x^2and4yx^2$$

$$y=\frac{1}{\left(2x^2+x\right)^3}$$

$$y'\:+\frac{y}{x+1}-\frac{1}{2}\cdot\left(x\:+\:1\right)^3\cdot y^2\:=\:0$$

$$80+8x-16x^2$$