$\left(-10w^4y^2z\right)\left(-3wy^3z^2\right)$
$\int\frac{x+3}{\left(3x+5\right)\left(4x^2+4x+1\right)}dx$
$\left(6x-3\right)\left(x+4\right)$
$-3x^2y+y$
$\log\frac{1}{7}\left(x\right)=4$
$\frac{-7x+12}{2}\le\:\frac{-x+9}{7}$
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