$\frac{dy}{dx}=-3y^2\ln\left(2x\right)$

$\lim_{x\to0}\left(\left(3x\right)in\left(x+1\right)\cdot cos\left(3x\right)\right)$

$x\:\frac{dy}{dx}-2x^2=y$

$\int\left(\frac{\left(x\right)}{\left(\sqrt{\left(\left(x^2\right)-1\right)}\right)}\right)dx$

$2x^2>4$

$6x^4+5x^3-136x^2+5x+300$