$x+6>=9$

$\sqrt{9\cdot1^2+12\cdot1\cdot2+4\cdot2^2}$

$\frac{dy}{dx}=\frac{1}{x^2}+\frac{2y}{x}$

$\int\frac{d\cdot x}{\left(x+3\right)\left(x+2\right)\left(x-1\right)}$

$3x^3+4x^2-7x+1+4x^3-5x^2+3$

$\lim_{x\to1}\left(\frac{3\sqrt{x^2-1}}{x^2-3x+2}\right)$

$x^5-4x^4+3x^3-8x^2+\:32x-24$