$\int\:\frac{2}{3}^{-3}dx$
$\int\frac{1}{\left(x^2+1\right)\left(x^2+x+3\right)}dx$
$14-\left(3-7\right)+\left(4-7-6\right)+1$
$24\cdot22$
$\frac{3}{sec\:x-tan\:x}$
$\frac{1}{4}\left(2x+1\right)-x<\frac{x}{6}-\frac{1}{3}$
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