$x^2+8x-2x-16$
$\frac{x^3\:+\:12x^2\:-\:13x}{x\:-\:1}$
$48m^3x^2-\:3mb^4$
$\frac{5+\cos\left(y\right)}{1+5\sec\left(y\right)}$
$2a^2=-6+8a$
$\lim_{x\to\infty}\left(\left(1+\:\frac{7}{x}\right)^{\frac{x}{4}}\right)$
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