∫136x2+1dx\int\frac{1}{\sqrt{36x^2+1}}dx∫36x2+11dx
(a− b) 2 − 18 (a − b) + 81 \left(a-\:b\right)\:2\:-\:18\:\left(a\:-\:b\right)\:+\:81\:(a−b)2−18(a−b)+81
(4y−1)(4y+7)\left(4y-1\right)\left(4y+7\right)(4y−1)(4y+7)
dydx−11x3y=0\frac{dy}{dx}-11x^3y=0dxdy−11x3y=0
dydx−y=cos(e−x)\frac{dy}{dx}-y=\cos\left(e^{-x}\right)dxdy−y=cos(e−x)
5(−8v+4)+5v5\left(-8v+4\right)+5v5(−8v+4)+5v
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