$\left(3x+\frac{1}{3}\right)^3$
$2\left(1+0.50\right)^8$
$ln\left(x^2-1\right)$
$4\cdot\left(1-x\right)\cdot x^3$
$\left(3+8i\right)\left(7-9i\right)$
$-4\:x\:-8\:x\:-1$
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