limx→5(x2−25x−3)\lim_{x\to5}\left(\frac{x^2-25}{x-3}\right)x→5lim(x−3x2−25)
93x+4=(36−27x)16−9x2\frac{9}{3x+4}=\frac{\left(36-27x\right)}{16-9x^2}3x+49=16−9x2(36−27x)
10x2+13x−310x^2+13x-310x2+13x−3
−1 ⋅6-1\:\cdot6−1⋅6
(1−7x3y2z)2\left(1-7x^3y^2z\right)^2(1−7x3y2z)2
63x−8163x-8163x−81
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