$4z^2-2y^2-8z$
$y'=\frac{xy\:+3x-y-3}{xy-2x+4y-8}$
$n+4-7\left(n-5\right)$
$\sqrt[3]{135x^7}-2\sqrt[3]{40}x^7$
$x^2+9-x^2-9$
$x^8\:\cdot x^{-3}$
$\frac{-4x^2+12x^4}{x-1}$
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