Exercise
$\frac{dy}{dx}=\frac{\left(xy^2-cos\left(2\right)sin\left(2\right)x\right)}{y\left(1-x^2\right)}$
Step-by-step Solution
Final answer to the exercise
$\frac{-\left(xy^2-\cos\left(2\right)\sin\left(2\right)x\right)^2}{2\left(y^2-\cos\left(2\right)\sin\left(2\right)\right)}+\frac{y^{6}}{6}-\frac{1}{2}\cos\left(2\right)\sin\left(2\right)y^{4}+\cos\left(2\right)^2\cdot \sin\left(2\right)^2\cdot \frac{1}{2}y^2+\frac{y^{6}x^2}{6}+\frac{1}{2}\cos\left(2\right)\sin\left(2\right)y^{4}x^2-\frac{1}{2}\cdot \cos\left(2\right)^2\cdot \sin\left(2\right)^2x^2y^2=C_0$