$-[-2+7-\left(-7+\left(-7\right)+2\right)-1]$
$5x+12,con\:x=3$
$2\cdot\left(\frac{x^{\frac{-2}{3}}\cdot\sqrt{2}}{0.5\cdot x}\right)^2=\sqrt[3]{\frac{x^{-1}}{2^{-3}}}$
$-0,3>u+7,8$
$\left(2t^2-t+3\right)\:\left(2t^2-1\right)$
$2x\le7$
$\int\frac{x}{\sqrt{8}}dx$
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