$\sqrt[0]{1}$
$\left(6x^2+y^3+1\right)^2$
$400\cdot60$
$x^2+16x+48$
$\left(4a-3\right)\left(4a+1\right)$
$\int\frac{2x+3}{\left(x+4\right)\left(x+6\right)}dx$
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