$\cos\left(x\right)\sin\left(x\right)=1$
$\frac{1}{2x^3}\:x\:\:\frac{7}{4x^6}$
$2\left(x\sqrt{2}\right)\left(4x\sqrt{2}\right)$
$\left(6y^3-8xy^2-6xy^2\right)-\left(xy^2-6y^3+4\right)$
$3^3\cdot\sqrt{4}-4^2$
$\frac{2x^2+x}{2x^2-1}$
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