$y'+3x^2+y=x^2$
$\left(3x+4\right)^2=9$
$\lim_{x\to0}\left(\frac{\cos\left(5x\right)-1}{x}\right)$
$5x^8-\:10x^7\:+\:10x^6$
$\frac{10^{-4}}{10^{-14}}$
$-x^2-6x-8$
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