(25x2)2\left(25x^2\right)^2(25x2)2
∫01(4r1−r4)dr\int_0^1\left(\frac{4r}{\sqrt{1-r^4}}\right)dr∫01(1−r44r)dr
dydx=e(y−ln(sqrt(x)))\frac{dy}{dx}=e^{\left(y-ln\left(sqrt\left(x\right)\right)\right)}dxdy=e(y−ln(sqrt(x)))
∫−14.50((2.509(x+14.5)(12))2 )dx\int_{-14.5}^0\left(\left(2.509\left(x+14.5\right)^{\left(\frac{1}{2}\right)}\right)^2\:\right)dx∫−14.50((2.509(x+14.5)(21))2)dx
dydx=0.022i(29−i)\frac{dy}{dx}=0.022i\left(29-i\right)dxdy=0.022i(29−i)
−4 − 2 −4 −7 +−72-4\:-\:2\:-4\:-7\:+-7^2−4−2−4−7+−72
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