$\frac{\left(\frac{x}{2}\right)^6-\left(\frac{1}{x^4}\right)^3}{\left(\frac{x}{2}\right)-\left(\frac{1}{x^4}\right)}$
$\int\left(x\cos\left(\frac{1}{2}x\right)\right)dx$
$2-sec^2z=1-tan^2z$
$x^4-6x^2+9$
$3x^2+12x+12$
$\frac{\left(n+12\right)^{2+n}}{-16^{5+n}}$
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