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Exercise

$\frac{dy}{dx}=-\frac{2y-10x+8}{-y+5x}$

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Final answer to the exercise

$\frac{1}{6}\left(-2y+10x-8\right)+\frac{20}{9}-\frac{20}{9}\ln\left(3\left(-2y+10x-8\right)+40\right)+\frac{4}{3}\ln\left(3\left(-2y+10x-8\right)+40\right)=x+C_0$

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