$9x^2-4>0$
$\left(10-x\right)y'=10y$
$\int\frac{1}{\left(x-1\right)\left(x-3\right)}dx$
$\left(x+14\right)\left(x+45\right)$
$b^5-6b^5+5b$
$8x-10=6x+6$
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