$\frac{dy}{dx}=\frac{1}{6x-42}$
$\int_{-1}^2\frac{3x}{x+4}dx$
$\int_9^4\left(\frac{x^2}{x+1}\right)dx$
$\int_e^{\infty}\left(\frac{1}{x\left(\ln\left(x\right)\right)^3}\right)dx$
$\int_2^{\infty}\left(\frac{lnx}{x}\right)dx$
$\int_1^{25}\frac{\left(\left(lnx\right)^5\right)}{4x}dx$
Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b
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