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Solving: ddx((1−4x)tanh(4x)−1)\frac{d}{dx}\left(\left(1-4x\right)\mathrm{tanh}\left(4x\right)^{-1}\right)
Solve instead: dydx((1−4x)tanh−1(4x))\frac{dy}{dx}\left(\left(1-4x\right)tanh^{-1}\left(4x\right)\right)
f(x)=(1-4x)tanh(4x)^(-1)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

dydx((1−4x)tanh−1(4x))\frac{dy}{dx}\left(\left(1-4x\right)tanh^{-1}\left(4x\right)\right)

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Final answer to the exercise

−4tanh(4x)+4(−1+4x)sech(4x)2tanh(4x)2\frac{-4}{\mathrm{tanh}\left(4x\right)}+\frac{4\left(-1+4x\right)\mathrm{sech}\left(4x\right)^2}{\mathrm{tanh}\left(4x\right)^{2}}

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dydx ((1−4x)tanh−1(4x))
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