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$\frac{dy}{dx}\left(y=x^{\text{4}}\left(x^3+4\right)^5\right)$

Final answer to the exercise

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Other solved exercises

$x^5-2x^2+x$

$-b^2=4b-20$

$u^3+w^3$

$\frac{x^2+2x-5}{x+1}$

$2,65+4,105$

$\lim_{x\to4}\left(\frac{x^2-2x}{x^2-4x+4}\right)$
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