$\left(4c-2d\right)\left(5c^2-6cd+3d^2\right)$
$\left(2a-3b+c\right)\left(2a-3b-c\right)$
$\int\left(\frac{2}{4+4\tan\left(u\right)^2}.\left(\frac{2\sqrt{3}}{3}\sec\left(u\right)^2\right)\right)du$
$\lim_{x\to3}\:x^2+3x$
$\frac{\sqrt{3}}{4}\left(3.5\right)^2$
$\left(r^3+25^3\right)$
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