∫21x24(x3+5)54dx\int\frac{21x^2}{4\left(x^3+5\right)^{\frac{5}{4}}}dx∫4(x3+5)4521x2dx
7⋅(5−8)7\cdot\left(5-8\right)7⋅(5−8)
y2−16y+65y^2-16y+65y2−16y+65
4x2−64x4x^2-64x4x2−64x
x−5 − 2(x−1) = 2(3−x)x-5\:-\:2\left(x-1\right)\:=\:2\left(3-x\right)x−5−2(x−1)=2(3−x)
2x2+2y2−12x+2y−1=02x^2+2y^2-12x+2y-1=02x2+2y2−12x+2y−1=0
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