$\frac{1-\cos\left(2x\right)}{\tan^2x}=2\cos^2x$
$\lim_{x\to2}5x^3+3x^2+4x-3$
$\frac{d}{dx}2\sqrt{1-3x}$
$\frac{1}{27}m^3n^3+m^6n^6$
$2 + x y = 1$
$\left(x^2+1\right)\left(1-2x\right)$
$z\left(4\right)=\frac{2\left(4\right)+1}{-3\left(3\right)+3}$
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