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Exercise

$\frac{x^2+13x+40}{x^2+10x-25}\cdot\frac{x+5}{x-4}$

Step-by-step Solution

1

Multiplying fractions $\frac{x^2+13x+40}{x^2+10x-25} \times \frac{x+5}{x-4}$

$\frac{\left(x^2+13x+40\right)\left(x+5\right)}{\left(x^2+10x-25\right)\left(x-4\right)}$

Final answer to the exercise

$\frac{\left(x^2+13x+40\right)\left(x+5\right)}{\left(x^2+10x-25\right)\left(x-4\right)}$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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