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Exercise

$\frac{x^2+4x-12}{x^2-64}.\frac{x^2+6x}{x^2-5x-24}$

Step-by-step Solution

1

Multiplying fractions $\frac{x^2+4x-12}{x^2-64} \times \frac{x^2+6x}{x^2-5x-24}$

$\frac{\left(x^2+4x-12\right)\left(x^2+6x\right)}{\left(x^2-64\right)\left(x^2-5x-24\right)}$

Final answer to the exercise

$\frac{\left(x^2+4x-12\right)\left(x^2+6x\right)}{\left(x^2-64\right)\left(x^2-5x-24\right)}$

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