Factor the difference of squares $x^4-8$ as the product of two bynomials: $a^2-b^2=(a+b)(a-b)$
The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
Simplify $\left(\sqrt[4]{8}\right)^2$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $\frac{1}{4}$ and $n$ equals $2$
Solve the product of difference of squares $-\left(\sqrt{8}+x^2\right)\left(\sqrt{8}-x^2\right)$
Simplify $\left(x^2\right)^2$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $2$ and $n$ equals $2$
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