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Exercise

$\frac{x^2-9}{a^2+7a-8}\cdot\frac{a^2-64}{x+3}$

Step-by-step Solution

1

Multiplying fractions $\frac{x^2-9}{a^2+7a-8} \times \frac{a^2-64}{x+3}$

$\frac{\left(x^2-9\right)\left(a^2-64\right)}{\left(a^2+7a-8\right)\left(x+3\right)}$

Final answer to the exercise

$\frac{\left(x^2-9\right)\left(a^2-64\right)}{\left(a^2+7a-8\right)\left(x+3\right)}$

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Main Topic: Equivalent Expressions

Two algebraic expressions are equivalent if they stay equal to each other, for any values their variables can take.

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