$-12,43+-9,41$
$\frac{sec\left(x\right)}{tan\left(x\right)\:+\:cot\left(x\right)}$
$\left(27x^3y^2-36x^2y-9xy\right)$
$\left(\frac{2^{3x+xy}+3^{y+1}-6}{2^{x+4}}\right)^{2y+2^x}$
$\frac{8\cdot5.71}{2}$
$x^2-25+0$
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